Comrad
New Member
Hi guys,
I was wondering if anyone could provide me with some insight into a little problem I have been thinking about lately. I apologise if this has been discussed in a previous thread, I didn't see it anywhere else.
So, here's the situation. My family has a holiday shack on a beach, in a community that has no mains power. Typically we use a generator to power the lights and what not in there, however, I was planning to go up there by myself in the near future, and, I do not have a generator. I do however own a 1000 watt pure sine wave inverter.
I have calculated the power draw from the shack to be a maximum of about 750 watts, and, my pure sine wave inverter would be able to handle the load, however, I wish to run this inverter off my car.
Now, I know a little about this stuff, so, here are the calculations I have done, I was wondering if anyone can point out any pit falls in my working, or, let me know if I am on the right track. I am also using a lot of estimations, so, if someone had real values, that'd be great as well.
Ok, so, I have a 2005 VZ executive, and, I figure that my battery would be about 45 amp hours, so, given that draw would be 750 watts, at 240v, I would have a current of 3.125 amps. Given that I don't want to damage my battery, I wouldn't want to take it below half charge, so, assuming that there are 22.5 amp hours available, that means I should be able to run the shack for 7.2 hours at full load before getting to half charge just on the battery.
I then though about having the car running. I am assuming an idle current of 30 amps being produced by the alternator so, provided I turned of the stereo, lights, etc... I should be able to get close to that delivered to the system. Assuming a charging voltage of 14v, means it would be producing 420 watts, so, my net loss is 750 - 420 = 330 watts.
Again, using the 240v supply at 330 watts means that I would be drawing, in effect, 1.375 amps, and using the 22.5 amp hour value from before, I would only get about 16.3 hours at full load before reaching half charge.
Does this sound right? Or am I completely missing something? Any help on the matter would be greatly appreciated.
I was wondering if anyone could provide me with some insight into a little problem I have been thinking about lately. I apologise if this has been discussed in a previous thread, I didn't see it anywhere else.
So, here's the situation. My family has a holiday shack on a beach, in a community that has no mains power. Typically we use a generator to power the lights and what not in there, however, I was planning to go up there by myself in the near future, and, I do not have a generator. I do however own a 1000 watt pure sine wave inverter.
I have calculated the power draw from the shack to be a maximum of about 750 watts, and, my pure sine wave inverter would be able to handle the load, however, I wish to run this inverter off my car.
Now, I know a little about this stuff, so, here are the calculations I have done, I was wondering if anyone can point out any pit falls in my working, or, let me know if I am on the right track. I am also using a lot of estimations, so, if someone had real values, that'd be great as well.
Ok, so, I have a 2005 VZ executive, and, I figure that my battery would be about 45 amp hours, so, given that draw would be 750 watts, at 240v, I would have a current of 3.125 amps. Given that I don't want to damage my battery, I wouldn't want to take it below half charge, so, assuming that there are 22.5 amp hours available, that means I should be able to run the shack for 7.2 hours at full load before getting to half charge just on the battery.
I then though about having the car running. I am assuming an idle current of 30 amps being produced by the alternator so, provided I turned of the stereo, lights, etc... I should be able to get close to that delivered to the system. Assuming a charging voltage of 14v, means it would be producing 420 watts, so, my net loss is 750 - 420 = 330 watts.
Again, using the 240v supply at 330 watts means that I would be drawing, in effect, 1.375 amps, and using the 22.5 amp hour value from before, I would only get about 16.3 hours at full load before reaching half charge.
Does this sound right? Or am I completely missing something? Any help on the matter would be greatly appreciated.